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文件名称:GraphDis

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  • 上传时间:
    2012-11-16
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    1.14mb
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两个图算法

完整工程

1、实现O(n + r)时间复杂度内,good guy和bad guy的匹配

2、在无环图中,寻找两点之间的路径数目-(1)There are two types of professional wrestlers: "good guys" and "bad guys." Between any pair of professional wrestlers,

  there may or may not be a rivalry. Suppose we have n professional wrestlers and we have a list of r pairs of wrestlers

  for which there are rivalries. Give an O(n+ r)-time algorithm that determines whether it is possible to designate some

  of the wrestlers as good guys and the remainder as bad guys such that each rivalry is between a good guy and a bad guy.

  If is it possible to perform such a designation, your algorithm should produce it.

(2)Write a program that takes as input a directed acyclic graph G = (V, E) and two vertices s and t,

  and returns the number of paths from s to t in G.
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下载文件列表

GraphDis/Debug/GraphDis.exe
GraphDis/Debug/GraphDis.ilk
GraphDis/Debug/GraphDis.pdb
GraphDis/GraphDis/BaseStructs.h
GraphDis/GraphDis/Constant.h
GraphDis/GraphDis/Debug/BuildLog.htm
GraphDis/GraphDis/Debug/Graph.obj
GraphDis/GraphDis/Debug/GraphDis.exe.intermediate.manifest
GraphDis/GraphDis/Debug/mt.dep
GraphDis/GraphDis/Debug/Test.obj
GraphDis/GraphDis/Debug/vc90.idb
GraphDis/GraphDis/Debug/vc90.pdb
GraphDis/GraphDis/Graph.cpp
GraphDis/GraphDis/Graph.h
GraphDis/GraphDis/graph.txt
GraphDis/GraphDis/GraphDis.vcproj
GraphDis/GraphDis/GraphDis.vcproj.acer-PC.Administrator.user
GraphDis/GraphDis/readme.txt
GraphDis/GraphDis/Release/BuildLog.htm
GraphDis/GraphDis/Release/Graph.obj
GraphDis/GraphDis/Release/GraphDis.exe.intermediate.manifest
GraphDis/GraphDis/Release/mt.dep
GraphDis/GraphDis/Release/Test.obj
GraphDis/GraphDis/Release/vc90.idb
GraphDis/GraphDis/Release/vc90.pdb
GraphDis/GraphDis/Test.cpp
GraphDis/GraphDis.ncb
GraphDis/GraphDis.sln
GraphDis/GraphDis.suo
GraphDis/Release/GraphDis.exe
GraphDis/Release/GraphDis.pdb
GraphDis/GraphDis/Debug
GraphDis/GraphDis/Release
GraphDis/Debug
GraphDis/GraphDis
GraphDis/Release
GraphDis

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