资源列表
cfugehu
- 解如何配置路由器的nat协议才能使广域网中的客户端访问局域网中的FTP服务器
pulldownresistorpullupresistor
- 介绍了上拉电阻下拉电阻及零电阻的常用数据，对系统设计有一定的借鉴意义-Introduced the pull-down resistor pull-up resistor and the commonly used zero-resistance data, the system design from a certain significance
class.xml.sitemap.generator.php.tar
- Regardless of the programming or scr ipting language used, it is always a good idea to insert comments in scr ipts, explaining what the next lines or block of code is trying to accomplish, how and/or why. Comments in batch files are usually plac
syslist
- Linux系统的系统调用序列以与之对应的系统调用号表格-Linux system system call sequence corresponding system call number Form
pscad134
- 本人做的关于pwm整流逆变的各种控制方案 方便大家学习-Various control programs on pwm rectifier inverter I do to facilitate learning
counter
- 基于KEIL 使用于51单片机 计数器功能 用LCD1602输出 模块化设计-51 single-chip counter function LCD1602 output modular design based KEIL
3z3
- 二中二三中三计算器由彩票预测网免费提供，希望能帮助彩票爱好者们。-Two or three of the three lottery prediction calculator provided by the network free of charge, hoping to help lottery fans.
jj
- printf(" 请输入％d个课程的代表值(<％d个字符):\\n" ,(*G).vexnum,MAX_NAME) for(i=0 i<(*G).vexnum ++i) /* 构造顶点向量 */ { scanf(" ％s" ,(*G).vertices[i].data) (*G).vertices[i].firstarc=NULL } printf(" 请输入％d个课程的学分值(<％d个字符):\
Particle_Swarm_Optimization
- simulation pso for wind mppt
juzenlianchen
- 1.能实现不同的个数的矩阵连乘. 2.最后矩阵大小是8X8. 3是最优的矩阵相乘. 描 述：给定n 个矩阵｛A1, A2,...,An｝，其中Ai与Ai+1是可乘的，i=1，2…，n-1。考察这n个矩阵的连乘积A1A2...An。矩阵A 和B 可乘的条件是矩阵A的列数等于矩阵B 的行数。若A 是一个p x q矩阵，B是一个q * r矩阵，则其乘积C=AB是一个p * r矩阵,需要pqr次数乘。-1. To achieve a number of different mat
Puzzle
- 通过单击与空白网格相邻的网格，可以将该网格显示的图片移动到空白网格中，那么可以用一个按钮代表一个网格，然后让每个按钮显示一个小图片，最后将这些按钮添加到一个面板中，并让这个面板采用网格布局。游戏是由16个格子组成的小游戏，通过给定的样图来拼图-By clicking the adjacent grid with blank grid, you can move the picture to a blank grid display grid, you can use a button repre
Rational-Rose-PowerDesign-visio
- Rational Rose、PowerDesign、visio这三个软件的功能与异同-Rational Rose, PowerDesign, visio three similarities and differences between software functionality and