资源列表
CE_OFDM
- ppt for basic channel estimation
tianxianyudianbo
- 紫蝶黄蜂撒凯迪拉克阿萨大苏打大家澳盘大家打撒打撒个-Purple Butterfly Hornets Cadillac Asa soda sprinkled all Australian plate sprinkle a fight we fight Caesar
DCT
- discrete cosine transform
basicpulseradar
- implement basic pulse radar in matlab
matlab-Genetic-Quantum-Algorithm
- 量子遗传算法matlab仿真源代码，免费下载-Genetic Quantum Algorithm
aaaa
- 项目处理文档，能够提供多种参考，尤其是在审计项目中-one project document,can provider some provider
ReadMe.Txt
- This a read me file describing how to enable a custom gina stub dll in windows xp-This is a read me file describing how to enable a custom gina stub dll in windows xp
u-blox6_ReceiverDescriptionProtocolSpec_(GPS.G6-S
- ublox gps module communication protocol
Soft Frequency Reuse Scheme for UTRAN LTE
- The objective of UTRA evolution study item is to develop a framework for the evolution of the 3GPP radio-access technology
CODES.ZIP
- Consists of fractional calculus, solving linear Fractional Order Differential Equations (FODE), Source code and comparison of various Mittag Leffler functions, Source code and #D representation Fractional Order Grunwald Letnikov Derivative, New Bhale
twin_protocol
- Twin Protocol sample code for satellite receiver
3zuoye
- 某市有一码头，每次仅容一辆船停泊装卸货，由于经常有船等候进港，部分人提出要扩建码头。经过调查历史资料发现，码头平均每月停船24艘，每艘船的停泊时间为24±20小时，相邻两艘船的到达时间间隔为30±15小时，如果一艘船因有船在港而等候1小时，其消耗成本为1000元。经预算，扩建码头大约需要1350万元，故市长决策如下：如果未来五年内停泊船只因等候的成本消耗总和超过扩建码头花费则扩建码头，否则，不予扩建。因此，希望你能够帮助市长做出决策。此问题已知到达的大概时间和大概停泊时间，对于此问题用概率统计的