文件名称:four
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计算成组滑动的滑窗检测器的最佳门限已知: 击中数N = 128, 组宽n = 8,PF =
10¡ 6,PD = 90 假设以下条件:
(a) 信号不起伏
(b) 忽略天线波束调制
1
(c) 计算PD时忽略目标区以外噪声的影响
组门限(第二门限)为K=8 滑窗的门限(第三门限)为L=16 (滑窗中包含的组数为16)
求解: 最佳的KOPT 和LOPT,对这题做了具体仿真实现。需要的朋友,一定知道很有用。-Optimal threshold calculated as group slidable window detector is known: hit number N = 128, the group width n = 8, PF = 106, PD = 90 assuming the following conditions: (a) signal is not undulation ( b) ignore the antenna beam modulation 1 (c) the calculation of PD ignored outside the target area noise of impact group door limit (the second door limit) for K = 8 sliding window of the door limit (third door limit) for L = 16 (sliding window contains group 16) to solve: the best of the KOPT the LOPT, these questions do specific simulation to achieve. A friend in need, we must know to be useful.
10¡ 6,PD = 90 假设以下条件:
(a) 信号不起伏
(b) 忽略天线波束调制
1
(c) 计算PD时忽略目标区以外噪声的影响
组门限(第二门限)为K=8 滑窗的门限(第三门限)为L=16 (滑窗中包含的组数为16)
求解: 最佳的KOPT 和LOPT,对这题做了具体仿真实现。需要的朋友,一定知道很有用。-Optimal threshold calculated as group slidable window detector is known: hit number N = 128, the group width n = 8, PF = 106, PD = 90 assuming the following conditions: (a) signal is not undulation ( b) ignore the antenna beam modulation 1 (c) the calculation of PD ignored outside the target area noise of impact group door limit (the second door limit) for K = 8 sliding window of the door limit (third door limit) for L = 16 (sliding window contains group 16) to solve: the best of the KOPT the LOPT, these questions do specific simulation to achieve. A friend in need, we must know to be useful.
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下载文件列表
第四题/
第四题/BMWD.asv
第四题/BMWD.m
第四题/子函数/
第四题/子函数/F_PD.m
第四题/子函数/F_PF.m
第四题/子函数/F_SNR.m
第四题/子函数/PND.m
第四题/子函数/PNF.m
第四题/BMWD.asv
第四题/BMWD.m
第四题/子函数/
第四题/子函数/F_PD.m
第四题/子函数/F_PF.m
第四题/子函数/F_SNR.m
第四题/子函数/PND.m
第四题/子函数/PNF.m
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