有2个数组：

　　ary1 db 12,-35,0,126,-90,-5,68,120,1,-19

　　ary2 db 24,25,0,-38,-89,99,68,100,2,-20

比较两个数组的对应位，将大的数放在ary1数组中，小的数放在ary2中（要求采用子程序格式）-There are two arrays:

ary1 db 12,-35,0,126,-90,-5,68,120,1,-19

ary2 db 24,25,0,-38,-89,99,68,100,2,-20

The corresponding bit of the comparison of the two arrays, the large number of on ary1 array, the small placed ary2 (subroutine format requires)