找一个最小的自然数，使它等于不同的两组三个自然数的三次幂之和，即找最小的x，使得：

x=a*a*a+b*b*b+c*c*c+d*d*d+e*e*e+f*f*f

其中，a,b,c,d,e,f都是自然数,a<=b<=c<=d<=e<=f [a,b,c]!=[d,e,f]

-To find a smallest natural number, so that it is equal to the third power of the two different sets of three of the natural numbers and, i.e. to find the minimum of x, such that: x = a* a* a+b* a b* b+c* c* c+d* d* d+e* e* e+f* f* f wherein a, b, c, d, e, and f are natural numbers, a < = b < = c < = d < = e < = f　[a, b, c,]! = [d, e, f]