文件名称:1
-
所属分类:
- 标签属性:
- 上传时间:2013-04-23
-
文件大小:685byte
-
已下载:0次
-
提 供 者:
-
相关连接:无下载说明:别用迅雷下载,失败请重下,重下不扣分!
介绍说明--下载内容来自于网络,使用问题请自行百度
2、 约瑟夫(Josephus)环问题:编号为1,2,3,…,n的n个人按顺时针方向围坐一圈,每人持有一个密码(正整数)。一开始任选一个正整数作为报数的上限值m,从第一个人开始按顺时针方向自1开始顺序报数,报到m时停止。报m的人出列,将他的密码作为新的m值,从他在顺时针方向上的下一人开始重新从1报数,如此下去,直到所有人全部出列为止。
建立n个人的单循环链表存储结构,运行结束后,输出依次出队的人的序号。
-2, Joseph (Josephus) ring problem: Number as 1, 2, 3, ..., n of the n individuals in a clockwise direction around a circle, each holding a password (a positive integer). The beginning optionally reported a positive integer as the number of the upper limit of m since an order number off a clockwise direction, starting from the first person to report m stop. Reported m the man out of the line, his password as the new value of m, start from the next person in the clockwise direction from a reported number, and so on, until all the columns until all. N individual single cycle linked list storage structure, the serial number of the team after the end of the run, the output turn out.
建立n个人的单循环链表存储结构,运行结束后,输出依次出队的人的序号。
-2, Joseph (Josephus) ring problem: Number as 1, 2, 3, ..., n of the n individuals in a clockwise direction around a circle, each holding a password (a positive integer). The beginning optionally reported a positive integer as the number of the upper limit of m since an order number off a clockwise direction, starting from the first person to report m stop. Reported m the man out of the line, his password as the new value of m, start from the next person in the clockwise direction from a reported number, and so on, until all the columns until all. N individual single cycle linked list storage structure, the serial number of the team after the end of the run, the output turn out.
(系统自动生成,下载前可以参看下载内容)
下载文件列表
1.c
本网站为编程资源及源代码搜集、介绍的搜索网站,版权归原作者所有! 粤ICP备11031372号
1999-2046 搜珍网 All Rights Reserved.