文件名称:2Josephus
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- 上传时间:2013-11-30
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约瑟夫(Josephus)环问题:编号为1,2,3,…,n的n个人按顺时针方向围坐一圈,每人持有一个密码(正整数)。一开始任选一个正整数作为报数的上限值m,从第一个人开始按顺时针方向自1开始顺序报数,报到m时停止。报m的人出列,将他的密码作为新的m值,从他在顺时针方向上的下一人开始重新从1报数,如此下去,直到所有人全部出列为止。建立n个人的单循环链表存储结构,运行结束后,输出依次出队的人的序号。-Joseph (Josephus) Central question: numbered 1,2,3, ..., n n individuals clockwise direction around a circle, each holding a password (positive integer). An optional start a positive integer as the upper limit of the number m, from the first person to start a clockwise direction from the beginning of the order number, report m stop. M out of newspaper columns, his password as the new value of m, starting from the next person on his re-clockwise direction from one number off, and so on, until all the columns so far. N round robin to establish a personal list storage structure, after the end of the run, the output sequence number of people out of the team.
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下载文件列表
2Josephus/Debug/Josephus.exe
2Josephus/Debug/Josephus.ilk
2Josephus/Debug/Josephus.obj
2Josephus/Debug/Josephus.pch
2Josephus/Debug/Josephus.pdb
2Josephus/Debug/vc60.idb
2Josephus/Debug/vc60.pdb
2Josephus/Josephus.c
2Josephus/Josephus.dsp
2Josephus/Josephus.dsw
2Josephus/Josephus.ncb
2Josephus/Josephus.opt
2Josephus/Josephus.plg
2Josephus/Debug
2Josephus
2Josephus/Debug/Josephus.ilk
2Josephus/Debug/Josephus.obj
2Josephus/Debug/Josephus.pch
2Josephus/Debug/Josephus.pdb
2Josephus/Debug/vc60.idb
2Josephus/Debug/vc60.pdb
2Josephus/Josephus.c
2Josephus/Josephus.dsp
2Josephus/Josephus.dsw
2Josephus/Josephus.ncb
2Josephus/Josephus.opt
2Josephus/Josephus.plg
2Josephus/Debug
2Josephus
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