有三户人家共拥有一座花园，每户人家的太太均需帮忙整理花园。A 太太工作了5 天，B 太太则工作了4 天，才将花园整理完毕。C 太太因为正身怀六甲无法加入她们的行列，便出了90元。请问这笔钱如何分给A、B 二位太太较为恰当？A 应得多少元？90/(5+4)*5=$50 元？如果这么想你就上当了！正确答案是60 元。如果没想通的话再想想吧。

下面回答一个一般性的问题：假定A 太太工作了x 天，B 太太工作了y 天，C 太太出了90元，则A 太太应得多少元？输入保证二位太太均应得到非负整数元钱。三个太太工作效率相同。

友情提示：本题有个小小的陷阱哦。如果答案错的话，认真检查一下代码吧。

输入第一行为数据组数T (T<=20)。每组数据仅一行，包含三个整数x, y, z (1<=x, y<=10,1<=z<=1000)。



对于每组数据，输出一个整数，即A 太太应得的金额（单位：元）。-There are a total of three people have a garden, each household is required to help organize the garden wife. A wife worked for five days, Mrs. B will work four days before the garden after finishing. C because being pregnant wife can not join them, will be out 90 yuan. May I ask how the money given to A, B two wife is more appropriate? A number of dollars deserve? 90/(5+4)* 5 = $ 50 dollars? If you think you fooled! The correct answer is 60 yuan. If you thought it through, then think again. The following answer to a general question: Assume A wife worked x days, Mrs. B y days worked, C wife out of the 90 yuan, then A wife should get the number of dollars? Enter the wife should get guaranteed two non-negative integers dollars. Three Mrs. same efficiency. Tips: This question has a little trap, oh. If the answer is wrong, carefully check the bar code. Input of the first behavioral data set number T (T < = 20). Each set of data for one line only, contains three integers x, y, z (1 < =