文件名称:final
-
所属分类:
- 标签属性:
- 上传时间:2015-06-10
-
文件大小:3.27kb
-
已下载:0次
-
提 供 者:
-
相关连接:无下载说明:别用迅雷下载,失败请重下,重下不扣分!
介绍说明--下载内容来自于网络,使用问题请自行百度
1.写一个程序,它先接收一个字符串,然后显示其中数字符的个数、英文字母的个数和字符串的长度。
2.模拟密码输入:假设数据库中有密码5201314,用户输入一个字符串,显示的时候全都以*出现,然后判断用户输入的字符串是否与数据库中密码相同,若相同,输出“Password Right!”,否则输出 “Password Error!”
3.写一个程序,它先接收一个字符串,然后抽去其中的空格,最后按相反的顺序显示这个改变后的字符串。
4.找出负数的个数
5.求阶乘-1. Write a program that first receives a string and then displays the length in which the number of characters and English letters and the number of strings.
2. Analog password: 5201314 suppose password, the user enters a string of all time display to* appear, and then determine if the string entered by the user and the same password , if the same output Password Right! otherwise, output Password Error!
3. Write a program, it first receives a string, and then removing all spaces, and finally display the string in reverse order after this change.
4. Find the number of negative
5. factorial
2.模拟密码输入:假设数据库中有密码5201314,用户输入一个字符串,显示的时候全都以*出现,然后判断用户输入的字符串是否与数据库中密码相同,若相同,输出“Password Right!”,否则输出 “Password Error!”
3.写一个程序,它先接收一个字符串,然后抽去其中的空格,最后按相反的顺序显示这个改变后的字符串。
4.找出负数的个数
5.求阶乘-1. Write a program that first receives a string and then displays the length in which the number of characters and English letters and the number of strings.
2. Analog password: 5201314 suppose password, the user enters a string of all time display to* appear, and then determine if the string entered by the user and the same password , if the same output Password Right! otherwise, output Password Error!
3. Write a program, it first receives a string, and then removing all spaces, and finally display the string in reverse order after this change.
4. Find the number of negative
5. factorial
(系统自动生成,下载前可以参看下载内容)
下载文件列表
3.final2.asm
1.final0.asm
2.final1.asm
5.FACT.asm
4.N_NE.ASM
1.final0.asm
2.final1.asm
5.FACT.asm
4.N_NE.ASM
本网站为编程资源及源代码搜集、介绍的搜索网站,版权归原作者所有! 粤ICP备11031372号
1999-2046 搜珍网 All Rights Reserved.