文件名称:2048
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如输入 w 1 2 a 5 4 s 11 2 d 13 4 d 9 2 ,表示用户依次进行了如下5次操作:
玩家向上滑动一次,之后在编号1的位置新出现一个数值为2的新增块
玩家向左滑动一次,之后在编号5的位置新出现一个数值为4的新增块
玩家向下滑动一次,之后在编号11的位置新出现一个数值为2的新增块
玩家向右滑动一次,之后在编号13的位置新出现一个数值为4的新增块
玩家向右滑动一次,之后在编号9的位置新出现一个数值为2的新增块
如果编号所在的位置不为空,则修改 编号 编号 16+1,并探索编号所在位置是否为空,弱编号位置不为空,则重复 编号 编号 16+1,直至探索编号位置为空,并增加新增块-The input w 1 2 a 5 4 s 11 2 d 13 4 d 9 2, indicates that the user turn the following five actions: Players slide up once, and then in the position number 1 of the emergence of a new value for the new block 2 players slide to the left once, after the number 5 position of the emergence of a new value for the new players to block a downward slide 4, after the No. 11 position in the emergence of a new value for the new 2 player sliding block once to the right, after the number 13 position in the emergence of a new value for the new players to block 4 slides right once, after No. 9 position emerging a new value for the location of the block 2 where if the number is not empty, then modify the number number 16+1, and explore the location number is empty, weak position number is not empty, then repeat number number 16+1, until the position is empty explore numbers and increase new block
玩家向上滑动一次,之后在编号1的位置新出现一个数值为2的新增块
玩家向左滑动一次,之后在编号5的位置新出现一个数值为4的新增块
玩家向下滑动一次,之后在编号11的位置新出现一个数值为2的新增块
玩家向右滑动一次,之后在编号13的位置新出现一个数值为4的新增块
玩家向右滑动一次,之后在编号9的位置新出现一个数值为2的新增块
如果编号所在的位置不为空,则修改 编号 编号 16+1,并探索编号所在位置是否为空,弱编号位置不为空,则重复 编号 编号 16+1,直至探索编号位置为空,并增加新增块-The input w 1 2 a 5 4 s 11 2 d 13 4 d 9 2, indicates that the user turn the following five actions: Players slide up once, and then in the position number 1 of the emergence of a new value for the new block 2 players slide to the left once, after the number 5 position of the emergence of a new value for the new players to block a downward slide 4, after the No. 11 position in the emergence of a new value for the new 2 player sliding block once to the right, after the number 13 position in the emergence of a new value for the new players to block 4 slides right once, after No. 9 position emerging a new value for the location of the block 2 where if the number is not empty, then modify the number number 16+1, and explore the location number is empty, weak position number is not empty, then repeat number number 16+1, until the position is empty explore numbers and increase new block
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游戏2048.cpp
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