文件名称:2
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2. 关于无线信道的多普勒谱,请回答以下问题:
(1) 在某些无线信道中,多普勒频移会引起无线信道输出信号的混叠。请描述产生混叠的各种原因;
(2) 无线信道中的多普勒谱有一种经典谱(classic spectrum),请解释产生这种谱形状的机理;
(3) 请用Simulink工具编写代码(S-Function方式),产生一单径瑞利信道,其多普勒谱为经典谱,其中移动速率为120km/h。并请描述:自己用计算机产生的经典谱是正确的依据。(2. Regarding the doppler spectrum of the wireless channel, please answer the following questions:
(1) in some wireless channels, doppler frequency shift will cause aliasing of the output signals of the wireless channel.Describe the various causes of aliasing;
(2) there is a classic spectrum in the doppler spectrum in the wireless channel, please explain the mechanism of producing this spectrum shape;
(3) please use Simulink tool to write code (s-function mode) to generate a single-path Rayleigh channel, whose doppler spectrum is the classical spectrum, in which the moving rate is 120km/h.And please describe: your own computer generated classical spectrum is the correct basis.)
(1) 在某些无线信道中,多普勒频移会引起无线信道输出信号的混叠。请描述产生混叠的各种原因;
(2) 无线信道中的多普勒谱有一种经典谱(classic spectrum),请解释产生这种谱形状的机理;
(3) 请用Simulink工具编写代码(S-Function方式),产生一单径瑞利信道,其多普勒谱为经典谱,其中移动速率为120km/h。并请描述:自己用计算机产生的经典谱是正确的依据。(2. Regarding the doppler spectrum of the wireless channel, please answer the following questions:
(1) in some wireless channels, doppler frequency shift will cause aliasing of the output signals of the wireless channel.Describe the various causes of aliasing;
(2) there is a classic spectrum in the doppler spectrum in the wireless channel, please explain the mechanism of producing this spectrum shape;
(3) please use Simulink tool to write code (s-function mode) to generate a single-path Rayleigh channel, whose doppler spectrum is the classical spectrum, in which the moving rate is 120km/h.And please describe: your own computer generated classical spectrum is the correct basis.)
相关搜索: 宽带无线通信2
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下载文件列表
文件名 | 大小 | 更新时间 |
---|---|---|
2 | 0 | 2019-01-15 |
2\Rayleigh_Fading.slx | 20692 | 2018-12-11 |
2\srch.m | 376 | 2018-12-10 |
2\第二题.docx | 196939 | 2018-12-11 |
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