文件名称:c语言练习题
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Exercise 5: ‘for’ and ‘do … while” repetition statements
1. Write a program which uses a do/while loop to print out the first 10 powers of 2 other than 0 (ie. it prints out the values of 21, 22, ..., 210). Use a for loop to do the same.
注意 pow 的返回值，与 整数之间如何显示
2.The constant p can be calculated by the infinite series:
p = 4 - 4/3 + 4/5 - 4/7 + 4/9 - 4/11 +....
给出通项公式
Write a C program that uses a do/while loop to calculate p using the series. The program should ask the user how many terms in the series should be used. Thus if the user enters ‘3’, then the program should calculate p as being 4 - 4/3 + 4/5.
Nested repetition
3. Write a program that prints the following diamond shape. You may use printf statements that print either a single asterisk (*) or a single blank. Maximize your use of repetition (with nested for statements) and minimize the number of printf statements.
*
***
*****
*******
*********
*******
*****
***
*
4. Write a program to print a table as follows:
1*1= 1
2*1= 2 2*2= 4
3*1= 3 3*2= 6 3*3= 9
….
9*1= 9 9*2=18 9*3=27 9*4=36 9*5=45 9*6=54 9*7=63 9*8=72 9*9=81
1. Write a program which uses a do/while loop to print out the first 10 powers of 2 other than 0 (ie. it prints out the values of 21, 22, ..., 210). Use a for loop to do the same.
注意 pow 的返回值，与 整数之间如何显示
2.The constant p can be calculated by the infinite series:
p = 4 - 4/3 + 4/5 - 4/7 + 4/9 - 4/11 +....
给出通项公式
Write a C program that uses a do/while loop to calculate p using the series. The program should ask the user how many terms in the series should be used. Thus if the user enters ‘3’, then the program should calculate p as being 4 - 4/3 + 4/5.
Nested repetition
3. Write a program that prints the following diamond shape. You may use printf statements that print either a single asterisk (*) or a single blank. Maximize your use of repetition (with nested for statements) and minimize the number of printf statements.
*
***
*****
*******
*********
*******
*****
***
*
4. Write a program to print a table as follows:
1*1= 1
2*1= 2 2*2= 4
3*1= 3 3*2= 6 3*3= 9
….
9*1= 9 9*2=18 9*3=27 9*4=36 9*5=45 9*6=54 9*7=63 9*8=72 9*9=81
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压缩包 : 2019213626-EX05.zip 列表 e5-4.c __MACOSX/._e5-4.c e5-1a.c __MACOSX/._e5-1a.c e5-1b.c __MACOSX/._e5-1b.c e5-2.c __MACOSX/._e5-2.c e5-3.c __MACOSX/._e5-3.c
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