扑克斗牛的规则是这样的 A是一点 。2是两点，依此类推。。10就是10点，J，Q，K 都是10点 ，不用大小鬼， 发五张牌 ，任意三张组合出整十的数，，就算是牛，剩下两张再组合。取个位数。。个位是多少就是牛几。。要是任意三张组合不出整十。那就是没牛。。。我想用C语言些出来 算出52张牌的组合 可以有多少种是有牛在里面的 并且牛几有多少中种-Bull of the rules of poker is that A is the first point. 2 is two points, and so on. . 10 is 10, J, Q, K are 10, not the size of a ghost, the five card combination of any three out of the whole number of ten, and even the cattle, and then the remaining two combinations. Take in the single digits. . How much is a bit a few cattle. . Arbitrary if not the entire portfolio 10 3. That is not cattle. . . I would like to use C language more calculated by a combination of 52 cards can have how many species there is cattle in the inside and the number of cattle in several species. .