这是我今天刚做的高数常用的两个算法:一是用Newton迭代法求根号值 二是用4级-4阶的R-K法解此方程y/=-y ,初值y(0)=1.

同时有些常见的编程技巧.

-This is what I did today, just a high number of commonly used two algorithms: One is Roots with Newton iteration number value another one is 4-4 bands RK Solving this equation y/=- y, the initial value y (0) = 1. At the same time some common programming techniques.