搜索资源列表
quadratic_equation_solver
- Shows the solutions of a Quadratic Equation
calc
- sample calculator And 2 equation and com/widgets/universal-converter
buy
- n元一次方程的解 用c++实现，整数解的问题-n-time equation
dandao
- 弹道方程的计算，非常适合搞飞行器设计的人士参考。-The calculation of the trajectory equation, ideal for those who engage in vehicle design reference.
a
- 程序运行后，给出6个菜单项的内容和输入提示，具体如下： 1. 数字排序 2. 字符查找 3. 矩阵变换 4. 结构体数组 5. 三次方程 6. 字符串删减 7. Goodbye!-Program runs six menu items and input prompts are given as follows: 1. Sort of figure 2. Characters find the three matrix to transform the structure array. Cubi
solve-the-equation-root
- Dichotomy method to solve the equation root Microsoft Visual Studio Solution File, Format Version 11.00 # Visual Studio 2010 Project("{8BC9CEB8-8B4A-11D0-8D11-00A0C91BC942}") = "二分法求解方程的根", "二分法求解方程的根\二分法求解方程的根.vcxproj", "{D9669C97-34C5-4009
campact
- 一维热传导方程紧致格式的有限差分程序，含计算结果-The compact format of the one-dimensional heat conduction equation finite difference program, including the calculation results
matlab
- 解ABCD的四元方程求解ABCD的值，并通过此值计算出电力器件vto，rt的值，从而使并联器件变得简单，有效-Solution ABCD equation solving the value of the ABCD and power devices VTO rt value calculated by this value, so that the the parallel device becomes simple, effective
b0b1b2b3
- 实现求线性回归方程的参数使用的是牛顿迭代法-Seeking to achieve the parameters of the linear regression equation using a Newton iteration
Niudun
- 牛顿迭代法方程，可以计算出牛顿迭代法的结果-Newton iteration equation, we can calculate the result of Newton iteration
Advection_Richtmeyer_1
- A fortran code to solve the advection equation using Richtmeyer method.
fangcheng
- 解一元二次方程,在复数范围内求解，并能输出根的个数。- Avoids solving quadratic equation, in solving complex scope, and can output the number of root.
forequation
- 用于计算方程的根，方法为二分法。根据数值计算书上编写的程序。-Root method used to calculate the equation of dichotomy. The book value calculated in accordance with written procedures.
Equation
- 求解一元二次方程的解，可以选择通过二分法，迭代法或牛顿迭代法求解-Solution for solving a quadratic equation, you can choose by dichotomy, iterative method or Newton iterative method for solving
CPP_Projects
- C++入门专周的3个综合项目实践，含详细的设计文档:（1）新生报到管理系统 （2）员工管理系统 （3）高精度算式测验。-C++ 3 个 integrated projects designed introductory week practice, with detailed design documents: (1) new report management system (2) Employee Management System (3) high-precision test equ
zhongguo
- 中国剩余定理(不互质的情况) 对互质的情况，处理起来比较方便，可以直接套模板 本题给出不互质的模线性方程组，求出满足方程的最小正整数解 方案：对于不互质的模线性方程组，可以进行方程组合并，求出合并后的方程的解，这样就可以很快地推出方程的最终解。-Chinese remainder theorem (not prime case) to prime, the process more convenient, you can directly set the template of th
integral16.3.3
- 通过梯形积分法，通过输入定义域，可求得固定方程的弧长-By trapezoidal integration, arc can be obtained by entering the domain with fixed equation
READ_SINEX
- 读取IGS数据中心提供的sinex文件 并恢复法方程-Read sinex file IGS data centers and to restore normal equation
quartic-equation-solver
- 本例程解决了一元四次方程求解的问题，方法是先将一元四次方程降解成一元三次方程，再求解。-This example show how to solve the quartic equation.
C4-3
- 对于一元二次方程ax^2 + bx + c 0,解可以分为很多情况。 若该方程有两个不相等实根，首先输出1，换行，然后从小到大输出两个实根，换行； 若该方程有两个相等实根，首先输出2，换行，然后输出这个这个实根，换行； 若该方程有一对共轭复根，输出3，换行； 若该方程有无解，输出4，换行； 若该方程有无穷个解，输出5，换行； 若该方程只有一个根，首先输出6，换行，然后输出这个跟，换行；-For a quadratic equation