搜索资源列表
C4
- 两个乒乓球队进行比赛,各出3人。甲队为a,b,c三人,乙队为x,y,z三人,已抽签决定比赛名单。有人向队员打听比赛的名单,a说他不和x比,c说他不和x,z比,请编程序找出三队赛手的名单。-Two table tennis team competition, each person 3. A team for a, b, c three B teams for the x, y, z three, has decided to match the list of drawing. It was a
racing
- C语言编写的赛车小游戏,大一课程设计做的-C language racing games, freshman year curriculum design to do
CarGameDemo
- 我写的3d赛车游戏源代码。dx9.0。包括子弹系统。碰撞检测等。-I wrote a 3d racing game source code. dx9.0. Including the bullet system. Collision detection.
tianji
- 田忌赛马问题 利用动态规划解决,很简洁-Tian Ji' s horse racing to use dynamic programming to solve the problem, it is simple and
Racing
- vc赛马程序实例的源码,希望可以对大家有所帮助-vc racing program source code examples, I hope you can help
Horce-Match
- 自己编的赛马程序,适合c语言课程设计。有一定独创性-Their series racing program, designed for c language courses. Have some originality
Car-Racing
- Car Racing source with vb6
Horsematch
- 管理赛马比赛的程序代码 可实现比赛选手与马的管理-Management of horse racing code game players, and horse management, etc.
vb3d
- 一款改进版的赛车游戏代码,很合适学习vb的同学使用-An improved version of the racing game code, suitable learning vb students
wuxianxiaoshu-
- 数学两人赛跑问题: 假如有两个人赛跑,全长25米,A在B前面10米,A的速度是每秒5米,B的速度是A的两倍。 这样,因为A在B的前面,B要超过他就要路过A之前的位置,当B到10米的时候,A到了15米。等B到15米时候17.5米。因为B到A需要时间。这时间A又到B前面去了。所以永远追不上。 可是。用数学方法。A:25-10=5t A用3秒。B:25=10t B只用2.5秒。能追上。 -Mathematical two race question: if two people rac
BUPT-racing-car-game
- 北邮数电实验代码,VHDL,点阵赛车游戏-BUPT number of electric experimental code, VHDL, dot racing game
timer-1602
- 可以作为赛车比赛计时器,1602显示,串口发送时间-Can be used as a racing timer, 1602, serial transmission time
Race
- 这是一款简单的赛车游戏。在C语言环境运行。-A simple racing game. In C language environment run.
HTML-picture-scroll
- html图片滚动 跑马方式:循环绕行,只跑一次就停住,来回往复运动 scrollamount=20 跑马速度:数越大越快-HTML picture rolling Valley: circulation bypass, only run once stopped, the reciprocating motion of scrollamount=20 racing speed: number more quickly
3d-moto-racing-evolved
- GAME KESUKAAN SAYA SEKE UNTUK HP N95-GAME KESUKAAN SAYA SEKE UNTUK HP N95
saimayouxi
- 小型赛马程序,代码详细,简单易懂,是课设专业程序-Small racing program, code detailed, easy to understand, is a lesson for professional programming
source
- 华为oj渊子赛马问题C++解决,华为oj充分系列-Huawei oj deep sub Racing C++ solve the problem, Huawei oj full series
Tian-racing
- 齐王和田忌均有n(1到100的整数)匹马,只有当田忌马的战力值大于齐威王马的战力值时, 田忌才能赢,问田忌最多能赢几场??其中战力值用整数表示-Tian racing
robocup3V3
- robocup比赛暨中国机器人公开赛3V3实体小车源代码,比赛用极好的-robocup China Robot Competition and Open Source 3V3 solid car, racing excellent
田忌赛马
- 田忌赛马算法 你一定听过田忌赛马的故事吧? 如果3匹马变成1000匹,齐王仍然让他的马按从优到劣的顺序出赛,田忌可以按任意顺序选择他的赛马出赛。赢一局,田忌可以得到200两银子,输一局,田忌就要输掉200两银子,平局的话不输不赢。 请问田忌最多能赢多少银子?(Tian Ji racing algorithm You must have heard the story of Tian Ji's horse race, haven't you? If 3 horses into 1