搜索资源列表
Fama
- 2. 农夫和小米问题：农夫、狐狸、鸡和米都在一条河的左岸，现在要把它们全部送到右岸去，农夫有一条船，过河时，除农夫外，船上至多能载狐狸、鸡和米中的一样。狐狸要吃鸡，鸡要吃米，除非农夫在那里。试编程求出所有能确保全部安全的过河的计划，并给出Visual Prolog程序。-2. Farmer and millet issues: the farmer, the fox, chicken and rice are in a river' s left bank, and now all of
SemanticPhotoSynthesis
- We propose a technique that allows a person to design a new photograph with substantially less effort. This paper presents a method that generates a composite image when a user types in nouns, such as “boat” and “sand.” The artist can optionally
yinyueyanzou
- 这是一个音乐程序，按大写字母“A”，唱乐曲“玛丽有只小羔羊”； 按大写字母“B”，唱乐曲“太湖船” 按大写字母“C”，唱乐曲“祝福歌” 按"X"鍵，退出-This is a music program, according to capital letters " A" , singing songs, " Mary had a lamb" by the capital letters " B" , sing the music &
river
- 智者:渡河问题 一个摆渡人要把一只狼一只羊和一捆菜运过河去.由于船很小,每次摆渡人至多只能带一样东西.另外,如果人不在旁边时,狼要吃羊,羊要吃菜.问这人怎样才能将他们运过河去. -Wise:摆渡人to cross the river to the issue of a wolf a sheep and a bunch of food shipped across the river. As the boat is very small, each only with a maximum
catfish-bounded-move
- remembered cartoon “Mermaid” when seeing the shell. In general I have remembered all animated cartoons which looked in the childhood. But the strong impression to me has made color of a picture. The picture consists from a combination of all colors f
sr
- 有四名商人各带一名仆人要过河，但船最多能载二人，商人已获得仆人的阴谋：在河的任一岸，只要浦人数超过商人数，仆人会将商人*并窃取货物。安排如何乘船的权力掌握在商人手中，你能为商人制定一个安全过河的策略吗？-The four businessmen with a servant to cross the river, but the ship can carry up to two persons, businessmen have been the servants of the plot: o
defeewqw
- 轻舟已过简单模块1.1模块,很不错的易语言模块，易爱好者可以下载使用-Module 1.1 Module boat passed a simple, very good and easy language modules, fans can download the easy to use
20110819_061055285
- 支持自动更新，龙舟全进全退全自动识别船长-Support for automatic updates, all in all dragon boat captain back automatic identification
FRAMER
- 一个农夫带着一只羊，一条狼和一颗白菜想从河的东岸到西岸去。河上仅有一条船。只有农夫一人会开船。假设他每次只能带一只羊，或者一条狼，或者一颗白菜过河，并且当人不在场时，狼和羊，或羊和白菜不能单独在一起，因为狼会吃羊，羊会吃白菜。试编写程序求出他带一只羊，一条狼和一颗白菜过河的所有办法。-A farmer with a sheep, a wolf and a cabbage would like to go from the eastern shore of the river to the Wes
boat
- 实现人鬼同船,三人三鬼安全渡河，要求：两边岸都要保证人的数量不比鬼少 否则人会被鬼吃掉 另外 船上最多两人-people and ghost
moton_planing_trackingcontrol
- 水面无人艇运动规划及三自由度自动控制的源创代码-The water unmanned boat movement planning and three degrees of freedom of automatic control of the source of a code
friend
- 3、 友元 编写C++程序完成以下功能： （1） 定义一个Boat和Car两个类，他们都具有私用属性——重量； （2） 编写一个函数，计算两者的重量和。 double TotalWeight(Boat& b, Car& c) -Friend write C++ program perform the following functions: (1) the definition of a Boat and Car two classes, they have private
javascriptNeedCalendar
- 功能超强的一款JS万年历，含农历日历，节气名称、特殊日期说明，如情人节、端午节、春节等信息，可以显示当前系统时间，很酷，你可以把界面再美化一下。-Super featured a JS calendar with lunar calendar, solar terms name, special date instructions, such as Valentine' s Day, the Dragon Boat Festival, Spring Festival and other i
Vp_Marine_1.2
- 利用vp进行海洋建模（此模型包括海浪和小船，船可*，并具有尾浪和侧面浪花效果），然后导出的c++文件-The vp ocean modeling (This model includes the waves and the boat, the boat can be freedom of movement, and with a the tail wave and side spray effect), and then export c++ file
chuanjiaoshi
- 三个传教士与三个野人渡河，只有传教士会划船，野人在岸上多于传教士会吃了传教士，一条船，只能带两个人，，用c语言实现野人与传教士问题-Three missionaries and three savage cross the river, only missionaries will be boating, Savage ashore than missionaries will eat the missionaries, a boat, only with two people, Savage
ais
- 判断是本船信息，还是他船信息 检测出电文号 对电文的解析-Judgment of the boat or other vessel information detected message on the message parsing
yuesifu
- 有N个旅客同乘一条船，因为严重超载，加上风高浪大，危险万分；因此船长告诉乘客，只有将全船一半的旅客投入海中，其余人才能幸免于难，无奈，大家只得同意这种办法，并议定N个人围成一圈，由第一个人数起，依次报数，数到第K人，便把他投入大海中，然后再从他的下一个人数起，数到第K人，再把他投入大海中，如此循环地进行，直到剩下N/2个乘客为止。问哪些位置是将被投入大海的位置？-There are N ride a boat with passengers because of severe overloadi
LineDemo
- 里面绘制了小船、旗子和云，同时图面会随着画布的大小变换而变换-Drawn inside the boat, the flag and clouds, while drawing with the canvas size will change and transformation
dilemma2
- Farmer s Dilemma Problem Another classic AI problem (cannibals and the missionary) in agricultural terms. The point is to get the farmer, the fox the cabbage and the goat across a stream. But the boat only holds 2 items. If left a
ai
- 有三个传教士和三个野人过河，只有一条能装下两个人的船，在河的任何一方或者船上，如果野人的人数大于牧师的人数，那么牧师就会被吃掉。设计方法让所有人安全渡河。-There are three missionaries and three Savage river, only one person can hold two boats, boat or on either side of the river, if the number is greater than the number of sa