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1029-Rabbit
- 中大oj（Sicily）1029的题目。这道题目主要是看清递归关系式而编即可。注意处理精度。本程序利用四位进位处理精度。-Problem The rabbits have powerful reproduction ability. One pair of adult rabbits can give birth to one pair of kid rabbits every month. And after m months, the kid rabbits can become adu
C2
- 收集了目前大学期末考试中18个重要的C程序源代码例题解答，还有24个待续。题目：古典问题：有一对兔子，从出生后第3个月起每个月都生一对兔子，小兔子长到第三个月 后每个月又生一对兔子，假如兔子都不死，问每个月的兔子总数为多少？-Collected at the end of the current university examinations 18 important example C source code to answer, there are 24 adjourned. Ti
SunZiSuanJing
- 孙子算经, 古人的东西, 其实很多题目都是从这里来的 （著名的 鸡兔同笼 问题）-Sun Zi Suan Jing, ancient things, in fact, a lot of topics here are from the (well-known problem of the chicken rabbit with cage)
jitu
- 养鸡场和养兔场也许会用到！哈哈 计算器！ 鸡兔同笼问题 计算器 初学者-木飞-Chicken farms and may be used rabbitry! Haha calculator! Rabbit with the question of the chicken cage calculator beginners- wooden fly
GPRS_TEST3
- Gprs test for Rabbit processor
rabbit
- 兔生子程序源代码，详细算法，程序简单易懂-rabbit
tuzimigong
- 小游戏兔子迷宫,可选择左右两条道路,由c++编写。-Small Game Rabbit Maze
MagicSet
- 传一个兔子的最经典的版本，现在网上几乎就找不到了，所以我把这个费了九牛二虎之力才找到的版本发给大家-Biography of a rabbit of the most classic version, and now almost can not find online, so I went to great lengths to find that the version distributed to you
MagicCony
- 魔法兔子主要实现了“系统检测”、“系统优化”、“超级工具”、“实用工具”、“任务管理”、“选项设置”的功能。通过这些功能菜单可以很好的对系统进行优化及管理。-Magic rabbit main achievement of the " system test" , " optimization" , " Super Tool" , " utility" , " Task Manager" , " option
Downloads
- Rabbit implementation. Rabbit has been released into the public domain and may be used freely for any purpose -Rabbit implementation. Rabbit has been released into the public domain and may be used freely for any purposeRabbit has been released i
punda
- Rabbit has been released into the public domain and may be used freely for any purpose Rabbit has been released into the public domain and may be used freely for any purpose Rabbit has been released into the public domain and may be used freely
Crypt-Rabbit-1.0.0
- RAbbit Implementation
Chicken-rabbit-with-cage
- 鸡兔同笼问题，满足数量关系即可的简单小程序。-Chickens and rabbits with cage to meet a number of relations can be a simple applet.
Rabbit
- 围绕着山顶有10个圆形排列的洞，狐狸要吃兔子，兔子说：“可以，但必须先找到我，我就藏身于这十个洞中的某个洞。你从第１个洞找，下次隔１个洞（即2号洞）找，第三次隔２个洞（即5号洞）找，再隔3个…以后在这个圆圈中如此类推，次数不限。”但狐狸从早到晚进进出出了1000次，仍没有找到兔子。 问兔子究竟藏在几号洞里？-Around the Peak 10 of the circular arrangement of holes, the fox eat the rabbit, the rabbit s
1
- 古典问题:有一对兔子，从出生后第3个月起每个月都生一对兔子，小兔 子长到第三个月后每个月又生一对兔子，假如兔子都不死，问每个月的兔子总数 为多少? -Classical question: one pair of rabbits, one pair of rabbits are born from the month from 3 months after birth, a small rabbit gave birth to one pair of rabbits grow up
118_10
- 狼找兔子问题：一座山周围有n个洞，顺时针编号为0,1,2,3,4,…，n-1。一只狼从狼从零号洞开始，顺时针方向计数，每当经过第m个洞时，就进洞找兔子。例如n=5，m=3，狼经过的洞依次为0,3,1,4,2,0。输入m，n。兔子有没有幸免的机会？如果有该藏在哪？-The Wolf find rabbits problem: a mountain have n holes, clockwise Numbers for 0,1,2,3,4,... , n- 1.A Wolf from the
febonaci
- c语言基础训练练习题 斐波那契兔子问题 初学者可以参考-c language basic training exercises Fibonacci deed rabbit beginners can refer to
WRITE_IDBLOCK
- 对rabbit芯片进行编程时，首次使用这芯片时。应先用先下载这程序，这样可以来确认芯片类型，设置MAC地址-On the rabbit-chip programming, for the first time to use this chip. Should first download this program, so you can confirm the chip type, set the MAC address
chicken-and-rabbit
- 经典的鸡兔同笼问题 即知道脚的数量求鸡和兔的数量 -chicken and rabbit problem
rabbit-hole-master
- rabbit hole attack detection