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zhexue05
- 进程同步,哲学家进餐共享临界区变量.定义信号量机制控制进程不互斥!-process synchronization, philosopher dining area share critical variables. Definition signal to the process control mechanism not contradict!
zhexuejiajinchan3
- 在Linux环境下，用C语言实现哲学家进程问题。-the Linux environment, using C language philosopher process.
philosopher
- 采用c语言实现哲学家进餐问题，实现进程机制的管理！-Using c language implementation philosopher dine and realize process of management mechanism
dine
- Dining Philosopher s Problem
Philosopher
- 关于操作系统哲学家进餐的动态演示程序，清晰的分析了死锁发生的情形和修正死锁。-Dining philosophers about the operating system dynamic presentation procedures, a clear analysis of the deadlock situation occurred and amendments to deadlock.
4
- unix下实现5个哲学家之间的取食和思考的问题的一个实验-unix implementation of five between the philosopher and consider the problem of feeding an experimental
philosopher
- 模拟“五个哲学家”问题该实验的要点是，解决并发环境下，多进程之间的同步与互斥问题。进程间的同步互斥必然涉及进程间的通信（信息交换）。-Simulation of the " five philosophers" problem of the main points of the experiment, the solution to complicated circumstances, between the multi-process synchronization and
bankerand-philosopher
- 模拟银行家算法解决哲学家问题的小程序，程序能正确运行完不会造成死锁。-Analog bankers algorithm to solve the problem of small philosopher, the program runs correctly completed without causing deadlock.
root.tar
- 有五个哲学家围坐在一圆桌旁，桌中央有一盘通心粉，每人面前有一只空盘子，每两人之间放一只筷子每个哲学家的行为是思考，感到饥饿，然后吃通心粉.为了吃通心粉，每个哲学家必须拿到两只筷子，并且每个人只能直接从自己的左边或右边去取筷子-There are five philosophers sitting around a round table, table center with a plate of pasta, there is an empty plate in front of each pe
philosopher
- 编制模拟“五个哲学家”问题的程序 目的： 学习和掌握并发进程同步的概念和方法。 要求： 1、程序语法 philosopher [ -t <time> ] <time>是哲学家进餐和沉思的持续时间值，缺省值为2秒。 2、五个哲学家的编号为0~4，分别用五个进程独立模拟。 3、程序的输出要简洁，仅输出每个哲学家进餐和沉思的信息。例如，当编号为3的哲学家在进餐时，就打印： philosopher 3 is eating