贪心算法解删数问题 运用C++ Delete a few greedy algorithm for solving the problem-Delete a few greedy algorithm for solving the problem

要求采用链表形式，求两个一元多项式的乘积：h3 = h1*h2。函数原型为：void multiplication( NODE * h1, NODE * h2, NODE * h3 )。-Require the use of a linked list, find the product of two one yuan polynomial: h3 = h1* h2. Function prototype: void multiplication (NODE* h1, NODE* h2, NOD