搜索资源列表
nljstate
- 采用NLJ随机搜索的方法辨识一个以状态方法表示的非线性系统。选其初值 a1(0) =50 , a2(0) =100 , a3(0) =100 , a4(0) =50 , a5(0) =10 , 选范围为 r(1)(i)=0.5 a(0)(i) , 取数据长度 L =40, t =0.005 , 性能指标 J= 。迭代计算结果得 a 的估计值 1=17.6043243, 1=17.5977, 2=72.9573, 3=51.3014, 4=22.9889, 5=5.99965, J = 0.000
math
- 矩阵运算:求逆、转置、相乘等,然后通过矩阵运算求多项式纠正的值,多项式如:X=a0+a1*x+a2*y+a3*x*x+a4*x*y+a5*y*y Y=b0+b1*x+b2*y+b3*x*x+b4*x*y+b5-Matrix operations: inversion, transpose, multiply, etc., and then through the matrix for computing the value of correct polynomial, polynomial