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evalf
- 熟悉matlab的人都会很清楚matlab中的feval()函数没法对匿名函数进行运算，当然更不可能执行当前路径之外或者说搜索路径之外的函数。还有eval只能执行字符串命令。 9 q2 u8 e" L& Y, E Z8 {然而evalf解决了上面的所有问题 -Matlab person familiar with the very clear matlab in feval () function can not be anonymous function of computing, of
Invariant_Line_Segment_Matching
- function Invariant_Line_Feature_Matching ___DEscr iptION___ Compare segmented line pairs as 4 dimentional line pair features ( Q1 , Q2 , Drelative , D? ) Example : Invariant_Line_Feature_Matching ( ) ___REFERENCE___ Paper 1 : L
we
- 七单元天线阵DOA估计 clear clc d=1 天线阵元的间距 lma=2 信号中心波长 q1=1*pi/4 q2=1*pi/3 q3=1*pi/6 q4=3*pi/4 四输入信号的方向 A1=[exp(-2*pi*j*d*[0:6]*cos(q1)/lma)] 求阵因子 A2=[exp(-2*pi*j*d*[0:6]*cos(q2)/lma)] A3=[exp(-2*pi*j*d*[0:6]*cos(q3)/lma)] A4=[exp(-2*
normfreq
- clear 从内存中清除变量和函数 exit 关闭MATLAB load 从磁盘中调入数据变量 pack 合并工作内存中的碎块 quit 退出MATLAB save 把内存变量存入磁盘 who 列出工作内存中的变量名 whos 列出工作内存中的变量细节 workspace 工作内存浏览器 -There is one outlier in the data of , but is not of data .For and the line of Q2 is in
rank_corr
- 利用数据拟合概率密度函数 建立可靠度分析所需的概率分布函数-There is one outlier in the data of , but is not of data .For and the line of Q2 is in the middle of the box, so there are not asymmetries for both and .
q2
- To find the decryption of an image.
Q2
- Q2是检测16—QAM信号，QPSK是输入为QPSK的MIMO系统的最大似然检测，ZF和MMSE算法-Q2 is detected the signal of the 16-QAM, QPSK maximum likelihood detector is input to QPSK MIMO system, ZF and MMSE algorithm
Q2.codes
- image processing handling transformation on images and anti blurt functions. for cleaning effects of ringing and other noises from image
Q2
- Run DC power flows and calculate network response of three tie lines for any additional MW transfer from Area to area-Run DC power flows and calculate network response of three tie lines for any additional MW transfer from Area to area
Q2
- ooio fopskf pdkf sdk lskf lsk sk sdk kdmdk sdkf kdmfk dsmf ksdm kdmfk sdmfk sdmkf sdmlfk msk msdfk smfk smdfk msdfk smfk smdfkds
HW1-Q2
- Vibration with force no damping
q2
- Optimization basic example solved
PROJECT2
- 1. 利用逆运动学算出直线路径从(320mm,-200mm,480mm) 到(320mm, 0mm,480mm)再到(320mm, 200mm,480mm)的对应机械臂各个关节的角度。 本实验将解出的从(320mm,-200mm,480mm) 到(320mm, 0mm,480mm)的各关节角度存入q.mat中。从(320mm, 0mm,480mm) 到(320mm, 200mm,480mm)的各关节角度存入q2.mat中。 -1 using inverse kinematics to c