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SPI-PRT
- 昨天在论坛上看到有人帖出了他写的并串转换VHDL代码，但是他自己说有问题，但是不知道怎么改。我大概看了一下，发现思路还是比较乱的。于是就写下了我自己的并串转换代码。-yesterday at the forum see someone points out his writing and string conversion VHDL code, But he said there are problems, but does not know how reform. I probably wat
sanxiang
- 使用本软件，可计算出中小型工程三相短路电流。 若已确认但尚未进行下步计算之前，发现输入的支路类型或数据有误，可单击窗体另行输入。 计算三相短路电流时，请确认短路点编号及对应的网络平均电压。 双击窗体，可以打印出窗体上的图象。但，应将打印机预设为A4纸型，横向打印。 文件打印至硬盘，可用Word软件处理后存档及打印。 本软件不采用通常的网络变换。而先建立电导增广矩阵，解此矩阵即可求出各节点电位以及各支路电压降、电流。之后，方按不同电源类型，分别采用恒定电压或机组运转曲
StudyMath
- 一个十以内加减法的自动出题系统，适合c＃初学者学习其中的写法。-within a 10 addition and subtraction out that the automatic system, suitable for beginners learning c # in which the wording.
parallel-dijkstra 并行化思路实现dijkstra算法
- 并行化思路实现dijkstra算法。假设有p个处理器，N个顶点。给每个处理器分配N/p个顶点，求出局部的最小值，复杂度为O (N/p)。然后后一半的处理器将自己的最小值发送给第前p/2个处理器。前一半处理器接收到传来的值后，与局部的最小值比较，作为新值。继续循环，直到剩下一个处理器为止。-Parallelized dijkstra algorithm. Suppose there is p a processor, N vertex. Give each processor distributi
Parallel-Computing-OpenMP-Hell
- 用OpemMP进行C++并行编程的入门例程,OpemMP carried out with C++ parallel programming routine entry
mega1280
- AVR ATmega1280 单片机串口通信 串口接收字符串，四个串口同时启用，具有通信超时处理功能-AVR ATmega1280 microcontroller serial communication serial port to receive a string, four serial ports is also enabled with a communication time-out processing
duzhihui
- MPI并行程序设计（都志辉）-源程序 绝版啦-MPI parallel programming (both Zhihui)- source code out of print啦
huxiangwenhou
- MPI的程序实现，任意进程间相互问候，在许多情况下需要任意两个进程之间都进行数据的交换，测试环境需要MPICH的安装-MPI program implementation, arbitrary process, greeting each other, in many cases, any two processes need to have carried out the exchange of data between the test environment requires the in
MonteCarloIntegral
- 这是利用MPI进行的编程，实现了 MonteCarlo method。在平台上可以正确运行，得出正确的结果。-This is carried out by the use of MPI programming, to achieve the MonteCarlo method. In the platform to run correctly, the correct results.
02mpi-mandel
- 用vc实现一个画出曼德勃罗特集的mpi并行程序。请先装mpi。-using vc to implement a mpi program which draw out the mandel set. Please install mpi first.
16X16led
- 1. LED的显示原理： 16×16扫描LED点阵的工作原理同8位扫描数码管类似。它有16个共阴极输出端口,每个共阴极对应有16个LED显示灯，所以其扫描译码地址需4位信号线（sel0-sel3），其汉字扫描码由16位段地址（l0-l15）输入。 通过时钟的每列扫描显示完整汉字。 2. 本试验实现输出“欢迎光临”四个汉字，采用两种格式输出：（1）依次从右向左连续输出；（2）单个汉字从上及下刷新输出。 -1. LED display Principle: 16 × 16 dot mat
DDZ
- 一个办公室打牌不需要拿钱出来的 全靠软件记.不会错.下班在结帐-Playing cards do not need an office to take money out of mind depend on software. Wrong. Working in the checkout
SPARSE_CODE_DEMO
- C++实现的稀疏矩阵类,可实现稀疏矩阵的存储计算等功能-Now, instead of using 2D, we will use doubly-linked lists to present sparse matrices. There are various methods of organizing doubly-linked-lists. We not only store elements of sparse matrices but also implement operations
buffer
- 把存储在缓冲区的数据取出并进行计算 缓冲区如何存储数据以及读取方式-To the data stored in the buffer and calculated out how to store data buffer and read mode
p2.34
- 计算练习:要求使用者输入每组运算的题量和出现数字的最大值,然后计算出随机出的计算题.电脑最后给出正确率.-Calculation exercises: ask the user to input the amount of each operation and the emergence of problems the maximum number, and then calculate the random out of the math. Finally, the accuracy of t
daoxianwang
- 导线网 水平网平差计算程序源码 按格式输入数据 就可对一个导线网进行平差及精度计算-Wire network level network adjustment calculation program source according to input data format can be carried out on a wire network adjustment and precision calculations
SOR
- SOR计算方法，可以对多元方程组进行解算。-SOR method of calculation can be carried out on multi-equations solver.
Prime
- JAVA多线程找质数。 输入为你想要创建的线程数和质数上限。 例： java PrimeSieve 10 3会利用三个线程输出10以下所有的质数-JAVA multi-threading to find prime numbers. Enter the number of threads you want to create the maximum number and quality. Example: java PrimeSieve 10 3 will make use of
grover_min
- 用GROVER搜无序数据库中的任一个数，把该数找出来，即找出该数在数据库中的下标。由于量子并行性计算的特点，精度高，迭代步数少-GROVER search disorderly database in any of a number, the number to find out, that is, to find out the subscr ipt of the number in the database. Due to the characteristics of quantum par
formbackold
- 使用IEEE33 BUS系統所求出來的匯流排電壓、相角、功率，是用前代回法求解電力潮流，希望對大家有幫助。-Seeking out the use the IEEE33 BUS system bus voltage, phase angle, power, with the previous generation back method for solving power flow, and I hope for all of us to help.