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TestHuiwen
- 简单java回文，拿去应付老师绰绰有余。-Simple java palindrome, taken more than enough to meet the teachers.
Poliandrom2
- It is a kind of problem where u must show that the number are palindrome number -It is a kind of problem where u must show that the number are palindrome number
huiwenshu
- 研究数字规律，给出一定长度的随机数看是否满足回文数-Research Digital rules give a certain length of random numbers to see if satisfied palindrome
PALINDROME
- Palindrome code.. this code checks whether the given no. is a palindrome or not...
判断是不是回文数
- 题目：一个5位数，判断它是不是回文数。即12321是回文数，个位与万位相同， 十位与千位相同。 -Topic: a 5 digits, judge is it palindromes number. Namely 12321 is palindrome Numbers, bits and ten thousand the same, 10 and one thousand the same.
java_5
- 一个5位数，判断它是不是回文数。即12321是回文数，个位与万位相同，十位与千位相同。-A 5-digit, determine if it is palindrome. That 12321 is a palindrome, a bit the same as ten thousand, ten and one thousand.
test-the-string
- 设计一个程序，，对输入的字符串进行检测，以判断该字符串是否是回文数据，并输出判断结果。如：“abcxcba”或“abccba”都是回文数据。-Palindrome detection
stu
- 最长公共子序列以及回文数解题报告，其中包含了几种LCS代码，和一个通用的LCS模板。有c++版和pascal版-Longest common subsequence problem solving and palindrome report, which contains several LCS code, and a generic template LCS. There c++ version and pascal version
C-program-for-palindrome
- c program for palindrome
Palindrome-number-in-c
- palindrome number in c
Program-to-Check-Palindrome-Number
- programe to chek palindrome number
CBVBBBVJRNRGRJ
- 题目：一个5位数，判断它是不是回文数。即12321是回文数，个位与万位相同，十位与千位相同。 1.程序分析 2.程序源 代码如下: #include stdio.h #include conio.h main( ) { long ge,shi,qian,wan,x scanf( ld ,&x) wan=x/10000 qian=x 10000/1000 shi=x 100/10 ge=x 10 if(ge
Test15
- c程序实现输入一个字符串，能判断是否为回文字符串(Enter a string to determine whether it is a palindrome string)