资源列表
stack
- 栈的基本运算 包括栈的初始化 元素的入栈出栈-The basic operations include the stack stack stack the stack initialization element
AM
- am的Matlab源程序，可以用于系统仿真-am
bairstow
- 解非线性方程 能过解复根 实根 但需要逼近-help you save equation conclude different answer
1001
- POJ1001 PASCAL源代码.poj.org Problems 1001-POJ1001 PASCAL Source Code.poj.org Problems 1001
led-Modbus
- led 显示源代码，带有Modbus可与单片机通讯读取单片机显示状态-led display source code, with Modbus can be used with single-chip communications to read single-chip display status
MyBaysSolvEqs
- 贝叶斯正则化求解线性方程组的解,对于不适定问题也可以求解-baysian regulation application in solving ill-posed linear equations
Colormoment
- Calculate the Color feature of the image
jiaozheng1
- 一个单位负反馈系统的滞后超前频域法校正，可直接在matlab中打开和运行-A unit negative feedback system lag correction ahead frequency domain method can directly open and run in matlab
sy8
- 动态数组的实现 设矩阵A,B,C都是3*3矩阵，矩阵元素为整数类型，要求： 1.3个矩阵都采用动态数组进行存储； 2.编写实现C=A+B的函数； 3.编写实现C=A*B的函数。-Set up to implement dynamic arrays matrices A, B, C are 3* 3 matrix, the matrix elements of type integer requirements: 1.3 matrices are used to store dyn
1302
- 1302时钟程序，欢迎您来下载，谢谢，来吧-1302 clock program, you are welcome to download, thank you, come on
0000
- 方法：把连续取N个采样值看成一个队列，队列的长度固定为N，每次采样到一个新数据放入队尾.-Method: Take the N consecutive sampled values as a queue, the queue length is fixed at N, each sample to a new data into the tail.
Judge2_mfcc
- 耳蜗实质上相当于一个滤波器组，耳蜗的滤波作用是在对数频率尺度上进行的，在1000HZ下，人耳的感知能力与频率成线性关系；而在1000HZ以上，人耳的感知能力与频率不构成线性关系，而更偏向于对数关系，这就使得人耳对低频信号比高频信号更敏感。Mel频率的提出是为了方便人耳对不同频率语音的感知特性的研究。频率与Mel频率的转换公式为-on logarithm frequency scale, under the 1000 hz, the perception of the human ear and