资源列表
Nqueenproblem
- 这个程序采用局部搜索算法（Local Search），速度很快， 在配置为奔腾200，内存64MB,上测试可以在 几秒钟内解一百万阶的皇后问题。-This procedure using a local search algorithm (Local Search), fast, in the configuration for the Pentium 200, RAM 64MB, the test solution in a few seconds of order 1 million
dian-zi-shi-zhong
- 实用的小程序，检验自己学习水平，练手的简单程序。电子时钟 -A small utility program, test their learning level, the simple program in hand. Electronic clock
tanchishe
- 贪吃蛇，用于初学者对游戏代码初步的了解，以便学习-Snake, for a preliminary understanding of the game code for beginners to learn
sixmen.py
- Six men morris draft of engine for automatic solving.
eight-queens-problem
- 解决八皇后问题：即在8X8格的国际象棋上摆放八个皇后，使其不能互相攻击，即任意两个皇后都不能处于同一行、同一列或同一斜线上，问有多少种摆法。-Solve the eight queens problem: that is placed on a 8X8 grid chess eight Queen, so that it can not attack each other, that is, any two Queens are not in the same line, same column
xiayibaiceng
- 适合初学者学习的下一百层小游戏，主要功能已实现，其他功能自行添加。-For beginners to learn the game at 100-story, the main feature was implemented, other features add their own.
material
- 3d游戏,材质处理引擎,要求directx 9.0和vc或vs编译环境
GuessExample
- 简单的猜数字游戏,我们喝酒的时候经常玩的那种，很有意思，我是个新手，多多关照-a simple game, we often drink the kind of play is very interesting, I am a novice, more concern
c-daima
- 扑克斗牛游戏：A是一点 。2是两点，依此类推。。10就是10点，J，Q，K 都是10点 ，不用大小鬼， 发五张牌 ，任意三张组合出整十的数，，就算是牛，剩下两张再组合。取个位数。。个位是多少就是牛几。。要是任意三张组合不出整十。那就是没牛-some games
piao_rodrigues_2
- 根据rodrigues公式求3×3 旋转矩阵the rodrigues formula: http://en.wikipedia.org/wiki/Rodrigues _rotation_formula-According to rodrigues formula for 3 × 3 rotation matrix the rodrigues formula: http://en.wikipedia.org/wiki/Rodrigues _rotation_formula
Player
- 大芒果有游戏进入代码?竺⒐
ppg
- simple game in c++of the power puff girls -simple game in c++of the power puff girls