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huiwenshu.rar
- 判断一个整数N 是不是回文数（10 进 制和2 进制都要是回文）：例如1，3，5 都 满足条件。,Determine an integer number N is not a palindrome (10 M and 2 M to be the palindrome): for example, have to meet conditions 1,3,5.
palindrome
- 回文的判断方式，c++实现，参照baidu上面的代码-Palindrome way the judge, c++ Achieve, in the light of the above code baidu
_ch301.c
- 回文判断,正与反都用相同的字符序列为准.用堆栈实现-Palindrome judge, is working with the anti-all with the same sequence of characters shall prevail. To use the stack to achieve
Practice1_15
- 找出回文数，就是在一定范围内找出顺读和倒读都一样的词语。-Palindrome identify a few, that is, a certain scope to identify cis and read back the words read are the same.
Stack
- 完成堆栈抽象数据类型的顺序、链式表示与实现。实现功能：数值转换，计算器（表达式求值），迷宫求解，判断某个字符串是否是回文 -Completion of the stack abstract data type of the order, said that with the realization of the chain. The realization of functions: numerical conversion calculator (expression evaluation
palindrome
- 回文判断 输入一个字符串可以判断是不是回文。-Determine palindrome
number4
- 回文判别 实验要求：称正读和反读都相同的字符序列为“回文”，如“abba”和“abccba”是“回文”，“abcde”和“ababab”则不是“回文”，试设计一个算法，判别读入的一个以@为结束符的字符序列是否是“回文”。 实验目的： 1、掌握循环队列的定义及应用； 2、掌握队列的基本操作； 3、进一步熟练掌握栈的基本操作及应用； 4、初步学会解决具体问题的算法设计。-Experimental identification requirements palindrome:
h
- 回文判断：对于一个从键盘输入的字符串，判断其是否为回文。回文即正反序相同。如“abba”是回文，而“abab”不是回文。-Palindrome judge: for a string from the keyboard input, determine whether the palindrome. Palindrome sequence that is the same as the pros and cons. Such as " abba" is a palindrome
hui
- 编程求100到999之间的回文数.（回文数是指正读与反读都一样的数,如：232）-Programming for between 100-999 palindrome number. (Number palindrome correction and anti-time reading the same few, such as: 232)
huiwen
- 判断字符串中是否存在回文 如abcbe中bcb就构成了回文-String to determine whether there is such as abcbe in palindrome form the palindrome bcb
Number
- 本程序用于回文数的判断，输入一位数字，可以判断其是否为回文数字，不是返回提示-This procedure used to determine palindrome number, enter a single digit, you can determine whether the palindrome figures, not to return to prompt
palindrome
- palindrome Programming
palindrome
- simple c program for palindrome...... (ex: madam)
palindrome
- 改程序的主要功能是他可以计算出一大串字符中的回文是什么，并且去掉标点-palindrome，a word or phrase that reads the same backward as forward
Judgment-palindrome
- 回文判断！既可以判断类似POP,LOL等样式的字母，顺着看和倒着看一样的！-Palindrome judge! Either to determine the style of letters similar to POP, LOL, along to see and look backwards!
Palindrome-judgment
- 此程序为回文判断程序，是基于C++语言环境下的一个面向对象程序，主要涉及到C++语言数组知识的应用，供C++初学者学习 -This program is a palindrome judgment program, is based on an object-oriented program C++ language environment, mainly related to the application of the knowledge of C++ language array, f
Palindrome
- 回文串,可以实现回文串的判断，忽略字符串中的英文字母的大小写-Palindrome string, string palindrome can judge ignored the letters in the string case
Maximum-palindrome-string
- 找出一个字符串中的最大回文字串，算法比较简洁明了，效率较高。-Find a string largest palindrome string algorithm is relatively simple and straightforward, high efficiency.
Palindrome-Number
- 判断一个数是否是回文数。一种比较简单易懂的好的方法。-Palindrome Number
To-determine--palindrome-characters
- 要求从键盘中输入字符串，判断该字符是否为回文字符。-To determine whether for palindrome characters