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2005102611013310480
- 最佳矩阵连乘 给定n个矩阵｛A1,A2,…An｝，其中Ai与A i+1是可乘的，i=1，2…，n-1。考察这n个矩阵的连乘积A1A2…An。矩阵A和B可乘的条件是矩阵A的列数等于矩阵B的行数。若A是一个p×q矩阵，B是一个q×r矩阵，则其乘积C=AB是一个p×r矩阵,需要pqr次数乘。 由于矩阵乘法满足结合律，故计算矩阵的连乘积可以有许多不同的计算次序。例如，设3个矩阵{A1,A2,A3}的维数分别为10×100，100×5，和5×50。若按加括号方式((A1A2)A3)计算，3个矩阵连乘积
NORMAN.ZIP
- 本代码为计算方法中的一种常用算法 分半法 代码很简单.-code for the calculation of a common algorithm half law code is very simple.
gaijinpingfanggenfa
- 改进平凡根法，算法绝对好， -improve ordinary-law, the algorithm absolute good, huh!
gaussfa
- 高斯法-Gauss law!
CiPu
- 词谱。根据输入的句子，自动检查符合的词牌。对于不合格律的字作特殊标记。-word spectrum. Depending on the input sentence, automatic checks with the tune. Law failed for the special characters for marking.
flying
- 一个小小的飞碟游戏,操作比较简单,但游戏规律性不容易捉摸.-a tiny flying saucer game and the operation simple, but the game is not easy to grasp the law.
ManegmentOfMemory
- 动态分区管理方式的主存分配回收模拟系统的设计——最先适应法-through dynamic management of the main deposit recovery simulation distribution system design -- the first to adapt to law
cyy
- C语言常用算法源代码 C语言常用算法源代码 C语言常用算法源代码 C语言常用算法源代码-C language source code commonly used algorithm commonly used algorithm C language source code algorithm commonly used C language source code used C language count source Law
Case9_3
- 球体碰撞的效果_3符合物理学的碰撞定律-入射角等于反射角.rar-ball collision Sheet_3 Can the effect of collisions with the law of physics-angle to the corner. Rar
knap
- 用贪婪法的策论，用非递归实现背包问题的求解，并求出放如背包中的物品．-greedy law with political discourse, the use of non - recursive Knapsack Problem Solving and sought release if the items backpack.
实现艺术清屏
- 问题的提出:我们在编制程序时,经常要用到清屏处理,如dos下的cls,Turbo C下的clrscr()等都具有清屏功能,但这些均为一般意义的清屏,并未显示其清屏规律.而有时为了达到清屏的艺术美观,往往对清屏有一些具体要求,如:开幕清屏 闭幕清屏 上清屏 下清屏 中清屏.为此,这里用C语言编制了几个子函数,用于程序中时,既可达到清屏的目的,有能增加屏幕的艺术美观.-the problem : we in the preparation of procedures, regular use of
模拟进程调度
- 模拟操作系统进程调度的算法采用时间片轮转法和优先权法-operating system simulation process scheduling algorithm-time Web-law and law priority
毕业设计1
- 可哟实现图像的 增强和图像的边缘监测的作用 ，对于卡法者来说可哦、JKDSJFO SFJOSISFHNOIFDJGDKGDOKGDOPFGKD-can achieve image enhancement and image on the brink of the role of monitoring, card law who can run, oh JKDSJFO SFJOSISFHNOIFDJGDKGDOKGDOPFGKD
MuLaw Decoder and Encode
- Mu Law Decoder and Encode
fenzhifa.rar
- 分治法的基本思想，掌握递归程序编写方法；使用分治法编程，求解线形序列中第k小元素。,Separation of the basic ideas, grasp the recursive programming methods the use of sub-rule law programming, solving linear sequence of the first k small element.
create-point
- Arcengine 二次开发创建点对象，包括沿线创建，角平分线创建，构造角度距离法，构造角度交点法，构造偏移点发，构造偏转角度法，构造平行线上点法，后方交会定点法等-Arcengine secondary development to create point objects, including along the creation, angle bisectors to create, construct point distance, point of intersection const
RBtree
- VC6++的红黑树结点插入的建树法，可以直接运行-VC6++ The red and black tree node inserted Jianshu law, can be directly run
fenzhi
- 算法设计程序设计中分支界限法的C++实现-Algorithm design process the design limits of the law branch of C++ to achieve
73462669danchunxing
- c++单纯型法，很好用的，真的，虽然不是本人自己编的，但不错的-c++ simple-type law, with very good, and really, though not my own, but good
kaitong
- 古典问题：有一对兔子，从出生后第3个月起每个月都生一对兔子，小兔子长到第三个月 后每个月又生一对兔子，假如兔子都不死，问每个月的兔子总数为多少？ 1.程序分析： 兔子的规律为数列1,1,2,3,5,8,13,21.... -Classical problem: There are a pair of rabbits, from the birth of the first 3 months of each month from birth to a pair of ra